How Do You Calculate the Oscillation Frequency of a Compressed Rubber Pad?

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To calculate the oscillation frequency of a compressed rubber pad, the angular frequency ω can be derived using the formula ω = sqrt(k/m), where k is the spring constant and m is the mass of the object. The spring constant k can be expressed as k = mg/x0, with x0 being the displacement of the pad. Substituting this into the angular frequency formula results in ω = sqrt(g/x0). The units of this equation yield radians per second, confirming that the frequency can be calculated using f = ω/(2π). The discussion clarifies the relationship between angular frequency and frequency while addressing unit consistency in the calculations.
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So, I'm trying to brush up on my undergrad physics, and I'm sure this is a bone-headed question, so please bear with me.

Homework Statement


A heavy object, when placed on a rubber pad that is to be used as a shock absorber, compresses the pad by 1cm. If the object is given a vertical tap, it will oscillate. Ignoring the damping, estimate the oscillation frequency. [The book I'm using actually gives the solution]

Homework Equations


x(t)=A*sin(sqrt(k/m)t+\phi)
ω=sqrt(k/m)
F=k|l-l0|

The Attempt at a Solution


We'll call x0 the equilibrium displacement, x0=1cm
k=spring constant of rubber
so
k(l-l0)=k*x0=mg (equilibrium)
gives us
k=(mg)/(x0)
then
ω=sqrt(k/m)
which eventually solves to
ω=sqrt(g/x0)

The book gives an answer of sqrt(980) rad/s. My question is given the units from ω=sqrt(g/x0) (meters, seconds, centimeters), how do they arrive at radians?
 
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X0 is 0.01 m. So the unit of sqrt(g/x0) is 1/s.
ω is the angular frequency, it is measured in radians/second, but radian is dimensionless. ω=2πf (f=frequency).

ehild
 
Makes sense. I actually just beefed the algebra cancelling my units. Thanks!
 
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