How Do You Calculate Time and Distance for Deceleration in Physics?

AI Thread Summary
To calculate time and distance for a particle decelerating according to the equation a = -kv, where k is a constant, one must integrate the acceleration to express velocity as a function of time. Starting with the initial conditions, the integration leads to the equation ln|v| = -kt + c. By applying the known values of initial velocity and velocity at t=2 s, the constants can be determined. Ultimately, the time T for the particle's speed to reduce to one-tenth of its initial value is found to be 3.32 seconds, with a corresponding distance D of 5.19 meters. This approach effectively combines calculus with physics to solve the problem.
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Homework Statement



A particle moving along a straight line decelerates according to a= -kv, where k is a constant and v is velocity. If its initial velocity at time t=0 iv v0=4 m/s and its velocity at time t=2 s is v = 1 m/s, determine the time T and corresponding distance D for the particle speed to be reduced to one-tenth of its initial value

ans T = 3.32 s, D = 5.19 M



Homework Equations





The Attempt at a Solution



I have never tried a problem like this.. I just need some instruction on how to start.

Thanks you very much!
 
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Mobz said:

Homework Statement



A particle moving along a straight line decelerates according to a= -kv, where k is a constant and v is velocity. If its initial velocity at time t=0 iv v0=4 m/s and its velocity at time t=2 s is v = 1 m/s, determine the time T and corresponding distance D for the particle speed to be reduced to one-tenth of its initial value

ans T = 3.32 s, D = 5.19 M

Homework Equations



The Attempt at a Solution



I have never tried a problem like this.. I just need some instruction on how to start.

Thanks you very much!

Welcome to PF.

Notice first your equation a = -kv expresses Acceleration as a variable in V.
Hence to develop an equation expressing V as a function of t you will need to integrate a which is dv/dt. Rearranging your equation you have then:

1/v*dv = -k*dt

Integrating you get something of the form:

ln|v| = -k*t + c

You can use the values given to determine the constants of the equation.
 
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