How do you convert from Decibels to SNR for use with Shannon's equation?

AI Thread Summary
To convert decibels (dB) to Signal-to-Noise Ratio (SNR) for Shannon's equation, use the formula SNR(dB) = 10 * log(S/N). To find SNR from a given dB value, divide the dB number by 10 and then raise 10 to that power. For example, 35 dB converts to SNR as 10^(35/10) = 10^3.5, which equals approximately 3162.3. This method applies universally, so for 20 dB, it would be 10^(20/10) = 100.
Comscistudent
Messages
18
Reaction score
0
Hi all,

It's been many years since I did Mathematics last and I'm having trouble converting from db to the format required by Shannon's formula.

I've googled and looked in the textbook but it's all a bit technical for me, I see logs and formula manipulation and go cross-eyed.

I understand that decibels represent a ratio of S/N. Can someone maybe show me how to convert from 20db to the relevant Snr for shannons? Please explain as if trying to teach it to a 5 year old :)

I have found the SNR = 10log(S/N) ,where log is to the base 10, and I have a worked example using this but I get lost with the manipulations. Is there any rough and ready conversion?

I'm studying for an exam, this isn't a case of I have a simple question to convert from 20db, if it helps please pick an arbitrary number of db for the example.

Many thanks in advance
 
Physics news on Phys.org
In case more info is needed -

35db is the SNR in the question
SNR(db) = 35 = 10log(SNR) (all logs are base 10)
SNR = 1035/10 = 103.5

Where does the 35/10 come from? if it was 20 db would it just be 20/10?
 
Ok so it turns out all you do is divide the decibels by 10 and raise 10 to this power. Example = 27 decibels = 102.7
 
Back
Top