How Do You Determine the Angle β for Light Traveling Parallel Inside a Prism?

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To determine the angle β for light traveling parallel inside an isosceles prism, one must apply Snell's law, which relates the angles of incidence and refraction to the indices of refraction. The goal is to express β in terms of the prism's apex angle α and its index of refraction n. A common approach involves setting up the equations using the refraction law and expressing the angles accordingly. However, the original poster is struggling to arrive at the correct answer and seeks detailed guidance on the solution process. Clear step-by-step assistance is requested to resolve the confusion.
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Homework Statement



There's one angle of incidence β onto a prism for which the light inside an isosceles prism travels parallel to the base and emerges at angle β.
(Figure 1)

Homework Equations




Find an expression for β in terms of the prism's apex angle α and index of refraction n.
http://session.masteringphysics.com/problemAsset/1384202/2/23.P58.jpg

The Attempt at a Solution


to Use refraction law: n1sin(betta1)=n2sin(betta2). Then express betta2 through alpha. But i am not getting the right answer
 
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haitianstudent said:

Homework Statement



There's one angle of incidence β onto a prism for which the light inside an isosceles prism travels parallel to the base and emerges at angle β.
(Figure 1)

Homework Equations




Find an expression for β in terms of the prism's apex angle α and index of refraction n.
23.P58.jpg


The Attempt at a Solution


to Use refraction law: n1sin(betta1)=n2sin(betta2). Then express betta2 through alpha. But i am not getting the right answer

Would you please show your work in detail?

ehild
 
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