How Do You Determine the Correct Phase Constant for a Wave?

AI Thread Summary
Determining the correct phase constant (ø) for a wave can be challenging, particularly when multiple values seem valid. In this case, the parameters A, K, λ, and ω are established, but the phase constant must ensure that the wave's behavior aligns with the initial conditions. The graph indicates that at x=0 and t=0, y=0, leading to possible solutions of ø = π, -π, or 0. However, since a positive velocity is required at t=1, ø cannot be 0, leaving both π and -π as candidates. Ultimately, while both values yield the same velocity sign, the correct phase constant is +π, illustrating that certain contexts may favor one solution over another.
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Homework Statement


I've attached the question where the graph can be found.
Essentially I have no problem determining A=0.04M K= 10π rad/m λ=0.2M ω=π/5 rad/s
I'm having trouble choosing what ø should be.


Homework Equations


y(x,t)= 0.04sin(10πx - π/5t +ø)


The Attempt at a Solution


Since the graph is for the particle at x=0 and t=0 and y=0
0=0.04sin(ø) solving for ø gives π, -π and 0

To try and determine the right phase constant I took the partial derivative to find the transverse velocity.
v(x,t)= (0.04)(-π/5)cos(10πx - π/5t +ø)
Since the particle has a positive velocity at t=1 , plugging in t=1 should give a positive velocity
Therefore ø can't = 0 since using 0 as a phase constant gives a negative velocity for t=1 and x=0
Problem is both plus and minus pi give the right velocity and I'm not sure how to pick the correct one. The correct answer is +π
I'd like to know in general as well how to pick the correct value. Thanks!
http://imageshack.com/a/img547/3680/2tjw.png
 
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You did it just right. Many (me too) intuitively fill in ##\phi##=0. But if you draw a sin(x), and pull it to the right, you see x=0 is moving down.
 
Okay thank you! I'm just wondering how you can tell the answer is positive pi and not negative since both would give the same sign for velocity
 
It does not make any difference if you pick ∏ or -∏.
cos(a+∏)=cos(a-∏)=-cos(a)
 
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