How Do You Determine the Correct Phase Constant for a Wave?

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Homework Help Overview

The discussion revolves around determining the correct phase constant for a wave function given specific parameters such as amplitude, wave number, wavelength, and angular frequency. Participants are examining the implications of different phase constant values on the wave's behavior at specific points in time and space.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to solve for the phase constant by analyzing the wave function at specific conditions (x=0, t=0, y=0) and considers the resulting velocities derived from the wave equation. Some participants question how to differentiate between the phase constants of +π and -π, noting that both yield the same sign for velocity at certain points.

Discussion Status

Participants are exploring the nuances of selecting the correct phase constant, with some suggesting that both +π and -π could be valid under certain conditions. There is an ongoing inquiry into the reasoning behind preferring one value over the other, indicating a productive exploration of the topic.

Contextual Notes

Participants are working within the constraints of the problem as presented, including the specific values for wave parameters and the requirement to determine the phase constant based on the behavior of the wave at given points. The original poster expresses a desire for general guidance on selecting the appropriate phase constant.

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Homework Statement


I've attached the question where the graph can be found.
Essentially I have no problem determining A=0.04M K= 10π rad/m λ=0.2M ω=π/5 rad/s
I'm having trouble choosing what ø should be.


Homework Equations


y(x,t)= 0.04sin(10πx - π/5t +ø)


The Attempt at a Solution


Since the graph is for the particle at x=0 and t=0 and y=0
0=0.04sin(ø) solving for ø gives π, -π and 0

To try and determine the right phase constant I took the partial derivative to find the transverse velocity.
v(x,t)= (0.04)(-π/5)cos(10πx - π/5t +ø)
Since the particle has a positive velocity at t=1 , plugging in t=1 should give a positive velocity
Therefore ø can't = 0 since using 0 as a phase constant gives a negative velocity for t=1 and x=0
Problem is both plus and minus pi give the right velocity and I'm not sure how to pick the correct one. The correct answer is +π
I'd like to know in general as well how to pick the correct value. Thanks!
http://imageshack.com/a/img547/3680/2tjw.png
 
Last edited by a moderator:
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You did it just right. Many (me too) intuitively fill in ##\phi##=0. But if you draw a sin(x), and pull it to the right, you see x=0 is moving down.
 
Okay thank you! I'm just wondering how you can tell the answer is positive pi and not negative since both would give the same sign for velocity
 
It does not make any difference if you pick ∏ or -∏.
cos(a+∏)=cos(a-∏)=-cos(a)
 

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