How do you find how far an object will go?

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To determine the range of a projectile launched from a cliff, the time to reach maximum height and the time to fall to the ground must be calculated separately, as the projectile does not return to its starting height. The total time of flight is approximately 14.8 seconds, with the projectile reaching a maximum height of 191 meters. Relevant equations for vertical motion under constant acceleration due to gravity are essential for solving the problem. The discussion emphasizes the importance of showing calculations and using the correct equations for accurate results. Understanding these principles is crucial for determining the projectile's range from the cliff's base.
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A projectile is shot from the edge of a cliff 172.0 m above the ground level with an initial speed of 66.00 m/s at an angle of 68.00 ° with the horizontal.
What is the range X of the projectile as measured from the base of the cliff?

I would normally use a range equation, but I didn't think that would work here since the object is not coming back to the starting height.
 
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For this, you can calculate the time required to reach its maximum height in the projectile. Moreover, after you have done this, you can calculate the time required to reach its minimum point from its maximum. Adding these two times will give you the time for the entire route. You can then apply this time in the horiztonal direction as its velocity.
 
sandy.bridge said:
For this, you can calculate the time required to reach its maximum height in the projectile. Moreover, after you have done this, you can calculate the time required to reach its minimum point from its maximum. Adding these two times will give you the time for the entire route. You can then apply this time in the horiztonal direction as its velocity.

the time it takes for the object to hit the ground is 14.8 seconds and the maximum height is 191 m. Now what do I do?
 
angiep410 said:
A projectile is shot from the edge of a cliff 172.0 m above the ground level with an initial speed of 66.00 m/s at an angle of 68.00 ° with the horizontal.
What is the range X of the projectile as measured from the base of the cliff?

I would normally use a range equation, but I didn't think that would work here since the object is not coming back to the starting height.

angiep410 said:
the time it takes for the object to hit the ground is 14.8 seconds and the maximum height is 191 m. Now what do I do?

How did you calculate those numbers? What equations did you use? If you show us your work, it would be easier to help you.
 
they were given to me
 
angiep410 said:
they were given to me

Part of the Homework Help Template that you were provided when you started this thread (and you deleted) asks for the Relevant Equations. What are the Relevant Equations for motion under the influence of a constant acceleration (gravity)?

And what is the equation for the vertical motion of a projectile as a function of Vo, Yo, a, and time? How would you apply that equation to this question? And use the hints you were given in Post #2...
 

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