How Do You Find the Weight of a Beam Using Spring Scales?

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To find the weight of the beam using two spring scales, the readings of 71 lb and 100 lb must be analyzed in relation to their angles. The net horizontal force is calculated as 100 cos 60 - 71 sin 45, which equals zero, confirming equilibrium. The net upward force is determined by adding the vertical components: 100 sin 60 and 71 sin 45, resulting in a total of 137 lb. This total represents the weight of the beam. Understanding the diagram and forces involved is crucial for solving the problem effectively.
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I am asked to do this.

"A uniform beam is attached to two springs scales as shown. The scales read 71 lb and 100 lb respectively. Find the wight of the beam."

http://img144.imageshack.us/my.php?image=phy8wq.png


I have no idea how to go on about solving this. please someone explain it to me like you would explain it to a child.

Thanks in advance.
 
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I'm not being awkward, but I don't understand the diagram one bit.
 
My guess is that the diagram is meant to show a rod held up by two strings,
one at 45 degrees with a tensiion of 71#, and the other at 60 degrees from the horizontal with a tension of 100#. This is consistent with their being no net horizontal force on the rod.
The net horizontal force is 100 cos 60 - 71 sin 45=0 (as it should).
The net upward force on the stick is 100 sin 60 + 71 sin 45 =87 + 50 = 137#,
which equals the weight of the stick.
 
I reccomended him here for help guys, don't make me look bad:)

That diagram IS funky though
 
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