How Do You Scale a Unit Vector to a Different Length?

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Calculus: Vectors QUICK HELP PLEASE!

Okay so i need a little help.

Heres the problem.

The question asks...

Find a vector that has the same direction as <-2,4,2> but has length 6.

So i Did the |v|= Sqrt( A1^2+A2^2+A3^2)= sqrt(24) which is how you begin to find the unit vector with the same direction. I get stumped on how to find it with length 6. The new vector with the same direction would be... <-2/Sqrt(24), 4/Sqrt(24), 2/Sqrt(24)... but.. what about the length of 6..?

Can anybody help me? What do i do with this length of 6?

... any help would be awesome!
 
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Say you scaled the original vector by the same amount in all 3 dimensions. Which way would the scaled vector point?
 
Do you just multiply everything by 6, or in your example by 3?
 
wtee85 said:
Do you just multiply everything by 6, or in your example by 3?

Hint: what is the manitude of the unit vector? :biggrin:
 
The magnitude of the unit vector is sqrt(24) as i stated above. That is sqrt(24) of the original vector.
 
? Help?
 
wtee85 said:
The magnitude of the unit vector is sqrt(24) as i stated above. That is sqrt(24) of the original vector.
No, it's one. That's why it is called " unit vector". So what do you have to do to get a vector of length 6 pointing in the same direction?
 
Do u multiply or divide by 6? I am seriously lost as in how to get the new vector which i have found the direction too, to get a length of 6.. I am totally lost. I would assume you multiply by 6, thus it would be length of 6?
 
That's right. Think of it as an stick which is one cm long and pointing in some direction - to get a stick with a length of 6 cm and pointing in the same direction, you have to stick six of these sticks together.
 
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Okay so i need to multiply the new vector by 6. That means <a1*6, a2*6,a3*6>? Do u see what i mean?
 
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