How Do You Simplify an Equation Involving Natural Logarithms?

[Curious6]

Hey, I really would appreciate some help with this one as I'm stuck on my coursework. It'll probably be easy for most of you but I forgot how to do this operation with logarithms. See this equation:

lny = lnx + BlnK + (1 - B)lnL.

How can I change that to one that removes the natural logarithms by means of using x = e^lnx? Thanks in advance!

 

[Curious6]

Thank you very much!

 

[HallsofIvy]

This is really hilarious! You ask for someone to do your homework for you, showing absolutely no work of your own, then someone gives you a WRONG answer and you accept it without a thought!


e^a+b is NOT equal to e^a+ e^b!

But A ln x= ln x^A and ln x+ ln y= ln xy. Use those to write the left hand side as a single logarithm.

 

[Curious6]

HallsofIvy, please react proportionately to the situation. It was just a simple question and no big deal; the equation was just one out of a couple of alternatives I could solve to proceed with my coursework. I felt it was an insignifcant question so I didn't really believe it necessary to show all my workings. Nevertheless, thank you for your input.

 

[Office_Shredder]

Curious, that is pretty proportional. The situation is extremely ironic, and from now on if someone posts a question without showing work, I'm going to offer three possible solution routes, only one of which is correct. Absolutely brilliant.

 

[Curious6]

The situation is extremely ironic.

Talking about sound judgement and proportionality...

 

[HallsofIvy]

Should I have said nothing and let you think you had a correct answer?
I don't dislike you that much!

I pointed out that you were making a mistake and explained how to get the correct answer. And you criticize me?