How Do You Simplify Complex Exponential Expressions Using Euler's Formula?

AI Thread Summary
To simplify the expression e^(i6theta)[(1+e^(-i10theta))/(1+e^(i2theta))], Euler's formula is essential, as it relates complex exponentials to trigonometric functions. The discussion emphasizes using trigonometric identities to rewrite the components in terms of cosines and sines. A key point is that e^(-iwt) does not equal -cos(wt) - jsin(wt); instead, it equals cos(wt) - isin(wt). Participants suggest starting with Euler's formula and manipulating the expression to achieve the desired form. Ultimately, the goal is to express the result solely in terms of cosines.
Larrytsai
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Homework Statement


Simplify the expression

e^(i6theta)[ (1+e^(-i10theta))/(1+e^i2theta)]

Answer should be in terms of cosines

but i don't know how to start this problem? :S

Also, does e^(-iwt) = - coswt -jsinwt?

K so I am thinking about Eulers formula, and I get an expression with Sines and cosines not just cosines =s
 
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Hi Larrytsai! :smile:

(hav a theta: θ and try using the X2 icon just above the Reply box :wink:)

hint: use Euler's formula and standard trigonometric identities to simplify 1 + e2iθ :wink:

(oh, and e-iθ = cosθ - isinθ)
 
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