How Do You Solve a Modified Atwood Machine Problem?

  • Thread starter Thread starter kindor
  • Start date Start date
  • Tags Tags
    Atwood
AI Thread Summary
To solve a modified Atwood machine problem involving masses m2 and m3, first determine the normal force and friction for each block. Next, modify the Atwood's equation to account for the incline and calculate the acceleration. Use kinematics equations to find the time it takes for each mass to reach the ground. Finally, subtract the time taken by m2 from that of m3 to find the time difference. This approach will also help in determining the landing spots of the two masses.
kindor
Messages
1
Reaction score
0

Homework Statement


What the time difference between the instance that m2 and m3 hit the floor?
How far are their landing spots?

The Attempt at a Solution


So far I have figured out the normal force of the two blocks each, and then I found the friction of them both.Here is my work so far and the question. I have no clue on what to do next.

http://imgur.com/YRnxb
 
Physics news on Phys.org
It's an Atwood's machine, so you should be able to modify the Atwood's equation for acceleration to fit the specifications for an incline, and then solve for acceleration. From there, I'm assuming you would use kinematics equations to solve for the time it takes for each block to travel the distance to the ground, and then subtract the time for mass 2 from mass 3 to solve for the time difference.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top