How Do You Solve for Acceleration and Tension in a Pulley System?

AI Thread Summary
To solve for acceleration and tension in a pulley system, the equations m1a = T and m2a = -T + m2g sin(45) are proposed. The normal force, represented by m2g cos(45), is acknowledged but deemed unnecessary unless friction is involved. The main confusion lies in whether to use m2a = -T + m2g sin(45) or m2a = T + m2g sin(45). Clarification on the correct formulation of these equations is sought, indicating a need for stronger foundational understanding in physics. Understanding the role of forces in the system is crucial for accurate calculations.
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Homework Statement



http://img69.imageshack.us/img69/2429/phyq1.jpg

Homework Equations


to find the acceleration of the 2 objects and the Tension Force.


The Attempt at a Solution



since only 1 pulley used, a=a1=a2, then
m1a=T (1)
m2a=-T+m2gsin45 (2)

i wonder what happen to the m2gcos 45?? and is the 2 equations right for my assumption? thanks
 
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m2gcos45 is the normal force applied by m2, which isn't really important unless friction is considered (or unless it's so big that something breaks).
 
but is the 2 equations right? because i am still ponder over m2a=-T+m2gsin45 or m2a=T+m2gsin45 ?? really sad my basic wasnt good...
 
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