How Do You Solve for X in a Basic Statics Problem?

  • Thread starter Thread starter Jim Newt
  • Start date Start date
  • Tags Tags
    Statics
AI Thread Summary
To solve for X in the given statics problem, the equations of equilibrium are applied: Sum Fx = 0 indicates no forces in the x-direction, while Sum Fy = 0 leads to the equation F1 + F2 - F3 = 0. The moment equation, Sum M = 0, is expressed as (F1)(X) - (F2)(L-X). By solving these equations simultaneously, the value of X can be determined. The approach appears to be correct based on the provided equations.
Jim Newt
Messages
25
Reaction score
0

Homework Statement



For the attached problem, I'm asked to solve for X



Homework Equations



Sum Fx = 0
Sum Fy = 0
Sum M = 0



The Attempt at a Solution



Sum Fx = 0 = No forces in x
Sum Fy = 0 = F1 + F2 - F3 = 0
Sum M = 0= (F1)(X) - (F2)(L-X)
 

Attachments

Physics news on Phys.org
Jim Newt said:

Homework Statement



For the attached problem, I'm asked to solve for X



Homework Equations



Sum Fx = 0
Sum Fy = 0
Sum M = 0



The Attempt at a Solution



Sum Fx = 0 = No forces in x
Sum Fy = 0 = F1 + F2 - F3 = 0
Sum M = 0= (F1)(X) - (F2)(L-X)

Looks good so far...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top