How Do You Solve the Second Derivative of a Potential Function in Physics?

cpamieta
Messages
8
Reaction score
0

Homework Statement


Well this is a physics problem, need find the potential function



Homework Equations


\Psi =Axe-kx A and k are constants
I need to find d2 \Psi/dx2


The Attempt at a Solution


I thought u would just take the derivative two times
but just d\Psi/dx = Ae-kx-kAxe-kx
Would i do something like this?
http://tutorial.math.lamar.edu/Classes/DE/Linear.aspx
thanks
 
Physics news on Phys.org
What's the problem with just differentiating it again?
 
i forgot how you do a differential equation, i have the solutions. I want to know how you do the dΨ/dx
i thought it would just be dΨ/dx= -A/ke-kx Its been a long summer lol
 
You don't have a differential equation. You're simply differentiating a function twice.

For this particular function, you need to use the product rule and chain rule, and you need to know how to differentiate a polynomial and an exponential.
 
o ok thxs the wolfan alpha thing said it was when i typed it in. It also gave somthing different
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top