How Do You Solve the Trigonometric Integral in Fluid Mechanics Research?

Victor2167
Messages
2
Reaction score
0
Working on some fluid mechanics research for flat plate boundary layer, stuck on this integral:

∫sin(∏y/2δ)dy for 0<y<δ

Any help would be deeply appreciated.
 
Physics news on Phys.org
What about -2δ/∏ cos(∏y/2δ) from 0<y<δ ?

Which evaluates to: -2δ/∏( cos(∏/2) - 1) = 2δ/∏
 
what method of integration is used to obtain that answer?
 
Is the integral you are doing
\int_{0}^{\delta} \sin\left( \frac{\pi y}{2 \delta} \right) dy
?

There is an obvious choice of substitution to do
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top