How Does a Magnetic Field Affect a Charged Particle's Motion?

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A charged particle in a magnetic field experiences forces that affect its motion without doing work, as the force is always perpendicular to the velocity. The x-component of the particle's velocity remains unchanged while it traverses the magnetic field. The force acting on the particle is directed in the negative z-direction, consistent with the right-hand rule. The particle follows a helical path due to the combination of its velocity and the magnetic force. The particle's speed does not vary since the magnetic force does not perform work on the particle.
vsage
Another magnetism question

A particle of mass 7 kg carrying a charge of 82 micro-Coulombs enters a uniform B field of intensity 9 T at a speed 92 m/s and at an angle of 25° with respect to the field lines as shown in the figure. (Positive y is up positive x is right the field is pointing in the positive x direction and positive z is coming out of the screen)

True/false

A) The field does a finite amount of work on the particle as the particle's trajectory is bent by the field.
B) The x-component of the particle's velocity is unchanged as it passes through the B-Field.
C) The Force on the particle is in the -z direction.
D) The particle follows a helical path.
E) The particle's speed varies as it passes through the B-Field.

I got these answers:
A. True Work = Fcos(theta) and theta is always 90 degrees
B. False magnitude of speed is always the same but direction changes
C. True - right hand rule
D. True - Force is negative z direction but acts circularly in the plane of the field
E. False - Speed can't vary since the force acts perpendicular to the velocity.

Which ones did I get wrong?
 
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Regarding (A), how can the field do work if the force is perpendicular to the direction of movement?
 
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