How Does a One-Dimensional Impulse Force Affect an Object's Motion?

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A one-dimensional impulse force is applied to a 3.0-kg object, and the discussion revolves around calculating the impulse's magnitude, average force, and final speed given an initial speed of 6.0 m/s. The impulse can be determined by finding the area under the force vs. time graph. The average force is calculated using the formula (f + f0)/2, leading to a value of 450 N. The participant expresses difficulty with the material provided by the instructor, indicating a need for clearer guidance. Understanding these calculations is essential for solving similar physics problems effectively.
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Homework Statement



A one-dimensional impulse force acts on a 3.0-kg object, as described in the graph below.

http://qaboard.cramster.com/Answer-Board/Image/2006714849276328846376778312506582.jpg

Find:
(a) The magnitude of the impulse given to the object.
(b) The magnitude of the average force.
(c) The final speed if the object had an initial speed of 6.0 m/s.


Homework Equations



F = (Po-P)/ (To-T)
?

The Attempt at a Solution



I have need some help here what my instructor has us read gives no help in solving 99% of our problems.


Thanks
 
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For a graph of y vs x, if you find the area under that graph, you get what the product xy represents.
 
ok so would (b) be
(f+fo)/2
(900+0)/2
450N
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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