How does a superconductivity cable achieve zero resistance?

AI Thread Summary
Superconductivity cables achieve zero resistance by incorporating superconducting filaments alongside conventional copper, where the superconducting path allows electricity to flow without any resistance. Although copper has its own resistance, the presence of the superconducting material means that the majority of the current will preferentially flow through the superconducting path, effectively rendering the overall resistance of the system zero. This phenomenon can be understood through the principle that current prefers the path of least resistance, which in this case is the superconducting filament. As a result, the current bypasses the copper entirely, leading to infinite conductivity in the superconducting path. This explanation highlights the unique properties of superconductors in electrical systems.
StephenP91
Messages
14
Reaction score
0
Well. I have the image of the question.

http://img99.imageshack.us/img99/6834/question5.png

Question b)ii).

I know that the total resistance of the cable is 0 even though the copper itself still has resistance. I just want to know how the combination of the Superconducting filaments combined with the copper itself makes the over all resistance 0.

Thank you,
Stephen.
 
Last edited by a moderator:
Physics news on Phys.org
Think of it has the electircity taking the easiest path.
If you have two resistors in parallel and one has twice the resistance of the other, then twice as much electricty will flow down the small resistance (the easiest path) as down the high resistance path.

With a superconductor, one of the paths is perfectly 'easy' so infinitely more times as much electricty will flow down this path as the copper.
Or looking at it the other way - none of the electricty will take the copper path and the overall conductivity is still zero.
 
I think I understand now. Because I is inversely proportional to R and because the filament's R is infinitely smaller than the copper's R, the filament gets infinitely more/all of the current.

Well that's how I've made sense of it. Whether it's right or not, I don't know.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top