How Does an Electron Move in a Magnetic Field?

AI Thread Summary
An electron moving perpendicular to a magnetic field of 0.54T traverses a circular path at a frequency calculated using the formula f = qB/2πm. Substituting the charge of the electron (-1.6 x 10^-19 C) and its mass (9.11 x 10^-31 kg) into the equation yields a frequency of approximately 11.9 GHz. This calculation demonstrates how charged particles behave in magnetic fields. For further understanding, consulting updated physics resources or practicing with examples is recommended. Understanding these principles is crucial for mastering electromagnetism concepts.
DramaFoYoMama
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I can't seem to figure this one out as my Physics book is outdated. An electron enters a magnetic field of .54T w/ vel. perp. to the direction of the field. At what frequency does the electron traverse a circular path? A little guidance in the right direction would be appreciated.
 
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Nevermind. I just figured it out. :)
 


To answer this question, we can use the equation for the frequency of a charged particle moving in a magnetic field:

f = qB/2πm

Where f is the frequency, q is the charge of the particle (in this case, the charge of an electron is -1.6 x 10^-19 Coulombs), B is the magnetic field strength (0.54T), and m is the mass of the particle (in this case, the mass of an electron is 9.11 x 10^-31 kg).

Plugging in these values, we get:

f = (-1.6 x 10^-19 C)(0.54T)/2π(9.11 x 10^-31 kg)

= 1.19 x 10^10 Hz

Therefore, the electron will traverse a circular path at a frequency of approximately 11.9 GHz (gigahertz).

I would recommend checking with your teacher or a more updated physics book for confirmation and further explanation. Additionally, you can also try looking up examples or practice problems online to further understand this concept.
 
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