How Does an Inductor's DC Behavior Affect Circuit Current Buildup?

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SUMMARY

The discussion focuses on calculating the maximum current (I_max) in a circuit containing a resistor (R) of 34.2 Ω and an inductor (L) of 152 mH, powered by a 33.7 V battery. The relevant equation used is I=I_max(1-e^(-t/T)), where T is the time constant calculated as T=L/R. Participants clarify that I_max represents the steady-state current when the inductor no longer influences the circuit, leading to the conclusion that I_max can be determined using Ohm's Law: I_max = V/R.

PREREQUISITES
  • Understanding of Ohm's Law and its application in circuits
  • Familiarity with inductors and their behavior in DC circuits
  • Knowledge of exponential functions and their role in circuit analysis
  • Basic grasp of time constants in RL circuits
NEXT STEPS
  • Study the derivation of the time constant in RL circuits
  • Learn about the transient response of inductors in DC circuits
  • Explore the relationship between voltage, current, and resistance in electrical circuits
  • Investigate practical applications of inductors in electronic devices
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Electrical engineering students, circuit designers, and anyone interested in understanding the dynamics of RL circuits and inductor behavior in DC applications.

strawberrysk8
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Homework Statement



Assume that resistor R has a resistance of 34.2 Ω, inductor L has an inductance of 152 mH (milli-Henry), and the battery has a voltage of 33.7 V. Also assume that the circuit elements are ideal.

If the switch S is closed suddenly, the time for the current to attain a value of 82.1 mA is...

Homework Equations



I=I_max(1-e^(-t/T))
T=L/R

The Attempt at a Solution



I need help finding I_max.

82.1 mA=I_max(1-e^(-t/(152/34.2)))

Why do they give me V?
 
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Hi strawberrysk8,

strawberrysk8 said:

Homework Statement



Assume that resistor R has a resistance of 34.2 Ω, inductor L has an inductance of 152 mH (milli-Henry), and the battery has a voltage of 33.7 V. Also assume that the circuit elements are ideal.

If the switch S is closed suddenly, the time for the current to attain a value of 82.1 mA is...

Homework Equations



I=I_max(1-e^(-t/T))
T=L/R

The Attempt at a Solution



I need help finding I_max.

82.1 mA=I_max(1-e^(-t/(152/34.2)))

Why do they give me V?

I_max is the current in the circuit after the current has stopped changing (reached its final value). At that point, the inductor is not affecting the circuit (has no voltage drop across it). So how can you find I_max?
 

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