How Does Coil Dimension Affect Magnetic Field Strength?

AI Thread Summary
The discussion focuses on calculating the magnetic field strength at the center of a flat coil made from copper wire with a specific resistance per unit length. The relevant equations include Ohm's law (V = IR) and the formula for magnetic field strength (B = u0 * n * I), where n represents the number of turns per unit length. Participants express confusion about determining the length of the coil in relation to the number of turns and the impact of coil dimensions on magnetic field strength. There is a consideration of how increasing the coil's length while maintaining the same turns per unit length could affect resistance and current, ultimately influencing the magnetic field. The conversation raises questions about whether there is a unique solution to the problem based on these variables.
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A piece of copper wire has a resistance per unit length of 6.40e-3 ohm/m. The wire is wound into a thin, flat coil of many turns that has a radius of 0.190 m. The ends of the wire are connected to a 12.0 V battery. Find the magnetic field strength at the center of the coil.

R/L = 6.40e-3 ohm/m
r = 0.190 m
V = 12.0 V
u0 = 4pi e -7 Tm/A
B = ? T

Equations:
V = IR (I = V/R)
B = u0 * n * I
so B = u0 * n * (V/R)

I don't know where to go from here.
 
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Start by finding L in terms of n. That may be your missing ingredient.
 
n = turns/L
L = R/6.40e-3 ?
im lost here
 
Did you post the question exactly?

What I'm thinking is... can't you arbitrarily make the coil longer, keeping the number of turns/unit length the same... but increasing the resistance... thereby lowering the current. And that would lower the magnetic field?

So is there a unique solution to this problem?
 
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