How Does Dimensional Analysis Prove mH Equals Force in Magnetism?

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In magnetism, the equation mH = F establishes that the product of pole strength (m) and magnetic field intensity (H) equals force (F). The dimensional analysis shows that the dimensions of mH correspond to [MLT^-2], which is the dimension of force. This relationship can be derived from the fundamental equation F = ma, where mass (M) is multiplied by acceleration (LT^-2). The discussion emphasizes that this is primarily an exercise in dimensional analysis rather than a deep exploration of magnetism itself. Understanding this relationship clarifies how magnetism relates to fundamental physical principles.
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In magnetism ,
mH = F, where m = pole strength ; H= magnetic field intensity ; and
F = Force.


F = [ MLT^{}-2]

Proof that dimension of mH = [MLT^{}-2]
 
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Can you figure out the dimensions from the units of m and H? What are you not understanding? You didn't really ask a question.
 
If you wish to proove from F=mH that mH has dimensions of MTL-2, just consider that mH is equal to a force, which is equal to mass times acceleration: M*LT-2.

This is not as much an excercise in magnetism as in rather basic dimensional analysis.
 
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