How Does Distance Affect Electric Flux Through a Square?

AI Thread Summary
The discussion centers on calculating the electric flux through a square due to a point charge located above it. The charge is -3.2μC, positioned at a distance of d/2 from the square's center, with the square having a side length of d = 0.34 cm. To determine the electric flux, the relationship between electric field and distance is crucial, as the electric field (E) is influenced by the distance from the charge to the square, represented as r in the equation E = kq/(r^2). The electric flux is calculated using the formula Flux = E dot dA, which requires finding the electric field through the square's area. Understanding how distance affects the electric field is essential for solving the problem accurately.
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Homework Statement


In the figure, a point charge -3.2μ C is a distance d/2 directly above the center of a square of side d = 0.34 cm . What is the magnitude of the electric flux through the square? (Hint: Think of the square as on face of a cube with edge d.)
(in N*m^2/C)


Homework Equations





The Attempt at a Solution


Ok so I am not asking specifically for the solution, but when the charge is located a specific distance from a finite plane such as this, how does the distance from the square(d/2) play into the solution?
 
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Well since Flux = E dot dA, you need to find the Electric field going through the side of the square. So the distance from the square is r in the equation for an electric field due to a point charge ( E = kq/(r^2) ).
 
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