How Does Elastic Collision Affect Particle Momentum?

  • Thread starter Thread starter Learning Curve
  • Start date Start date
  • Tags Tags
    Momentum Particle
AI Thread Summary
In an elastic collision involving a proton and a stationary particle, the conservation of momentum and kinetic energy principles apply. The initial momentum of the proton is calculated as 1.006 x 10^-20 kg(Mm/s), and after rebounding at 3.6 Mm/s, the equation for momentum conservation is set up. The unknown particle's momentum is represented as P2, which is derived from the equation involving the proton's momentum before and after the collision. To find the mass of the unknown particle, the velocity of this particle must be determined using the relationship between their velocities in elastic collisions. Understanding these principles will lead to the solution for the unknown mass.
Learning Curve
Messages
116
Reaction score
0
Here's a question from my workbook that I can't seem to figure out.

A proton (mass = 1.6 x 10^27 kg) moves with a speed of 6 Mm/s. Upon colliding elastically with a stationary particle of unknown mass, the proton rebounds on its own path with a speed of 3.6 Mm/s. Find the mass of the unknown particle.

Let's start with what I know. I know that momentum = mass times velocity.
or p = mv

I also know that since it's elastic, it isn't losing any energy.

So I used the equation P1 + P2 = P1 + P2

(1.67 x 10^-27 kg)(6 Mm/s) + 0 = (1.67 x 10^-27 kg)(-3.6 Mm/s) + P2

I said 3.6 Mm/s was negative since it was in the opposite direction.

So from there I got:

3.006 x 10^-20 kg(Mm/s) = 1.08216 x 10^-26 kg(Mm/s) + P2

P2 = 1.923 x 10^-26

But, from there I'm not sure where to go. I'm trying to find the mass of this particle, but I need to know it's velocity. :frown: Any help or hints is appreciated.
 
Physics news on Phys.org
The relative velocities of the bodies before and after an elastic collision have a predictable relationship. You could use that to find the mass.

Dorothy
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top