How Does Force Distribution Affect Two Blocks on a Frictionless Table?

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When a horizontal force is applied to a larger block on a frictionless table, it transmits a force to a smaller block in contact with it. The calculated force between the two blocks is influenced by their masses and the acceleration caused by the applied force. Specifically, when a 3.2 N force is applied to the larger block, the force between the blocks is determined to be greater than when the same force is applied to the smaller block in the opposite direction, resulting in a lower force of 2.1 N. This discrepancy arises because the mass of the blocks affects how the force is distributed between them. Understanding the relationship between mass, force, and acceleration is crucial in analyzing the dynamics of the system.
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OK, this should be my last question. Again, I need an answer soon, but I'm also here to learn.

Two Blocks are in contact on a frictionless table, one larger than the other. A horizontal force is applied to the larger block, pushing against the smaller block. (a) If m_A = 2.3 kg (the larger block), m_B = 1.2 kg (the smaller block), and F = 3.2 N, find the magnitude of the force between the two blocks. (b) Show that if a force of the same magnitude F is applied to the smaller block but in the opposite direction, the magnitude of the force between the blocks is 2.1 N, which is not the same value calculated in (a). (c) Explain the difference. I'm not quite sure what to do with the information given, so again, any help would be great!
 
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One has enough information.

Since the blocks are in contact, the applied for F acts on the mass of both (both must be accelerating), BUT, the force acting on (transmitted to) the larger block by the smaller block is less than the force that the larger block would apply to the smaller block - because . . . (what does mass do?)

Think F = ma.
 

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