How does friction act between PA and AB in an equilibrium of forces system?

AI Thread Summary
The discussion focuses on understanding the frictional force between points PA and AB in a system at equilibrium. Participants emphasize the importance of identifying all forces and their directions before determining the angle between PA and AB. It is clarified that friction acts parallel to the contact surface, which is crucial for solving the problem. The direction of the frictional force can be assumed initially, and if incorrect, adjustments can be made based on the results. Overall, a clear understanding of the forces involved is essential for accurately resolving the problem.
nickyfernandezzz
Messages
18
Reaction score
2

Homework Statement


The original question was to find the value of the angle between PA and AB. I have a certain idea regarding how to find it, but first I have to identify all forces acting on the system and their directions. So, I would be grateful if someone can explain how the frictional force acts between PA
and AB.

MY ATTEMPT.
I got a start by marking the forces acting on the system but I can't figure out the direction of frictional force.
 

Attachments

  • IMG_20170117_100516.jpg
    IMG_20170117_100516.jpg
    21.9 KB · Views: 458
  • IMG_20170117_101835.jpg
    IMG_20170117_101835.jpg
    20.3 KB · Views: 435
Physics news on Phys.org
nickyfernandezzz said:

Homework Statement


The original question was to find the value of the angle between PA and AB. I have a certain idea regarding how to find it, but first I have to identify all forces acting on the system and their directions. So, I would be grateful if someone can explain how the frictional force acts between PA
and AB.

MY ATTEMPT.
I got a start by marking the forces acting on the system but I can't figure out the direction of frictional force.
Some verbal statement of the problem would be enlightening.
You have marked mg at point Q, but that does not look like the centre.
I assume you are asking about the direction of the frictional force at A. Generally speaking, you do not need to figure that out in advance. Just assume it is one way along the surface, and if you are wrong it should become obvious (and it might just be a matter of flipping the sign to get the right answer).
 
haruspex said:
Some verbal statement of the problem would be enlightening.
You have marked mg at point Q, but that does not look like the centre.
I assume you are asking about the direction of the frictional force at A. Generally speaking, you do not need to figure that out in advance. Just assume it is one way along the surface, and if you are wrong it should become obvious (and it might just be a matter of flipping the sign to get the right answer).
I'm sorry for not being very clear. Actually, it was stated in the question that Q is the centre of AB.
So, is the friction acting ALONG the surface PA ( either upwards or downwards)?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top