How Does Friction Affect the Movement of a Thrown Turkey?

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The discussion centers on calculating the work done by friction on a 10 kg frozen turkey thrown horizontally across a surface with a coefficient of kinetic friction of 0.10. The user correctly calculates the weight of the turkey as 98.1 N and determines the kinetic friction force to be 9.81 N. Using the work equation, they find the work done by friction to be 98.1 Joules. To find the initial speed of the turkey, they apply the work-energy principle, resulting in a speed of 4.43 m/s. The calculations are confirmed as correct by other participants in the thread.
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Homework Statement



Alright well the problem is that 10 kg frozen turkey is thrown and goes horizontally on a surface with a 0.10 coefficient of kinetic friction. It travels for 10 meters. What is the work the friction does to stop the object. And what is the speed the frozen turkey is thrown at?

Homework Equations



eq.

W=f * d



The Attempt at a Solution



I did the problem I don't know if it is right, I am hoping you guys will tell me if I did.

First I got the weight of the turkey.
10 kg * 9.81 m/s^2 = 98.1 N downward

Then 98.1N * Coefficient of .10 = 9.81 N kinetic friction.

Then plugged that into the work equation W=9.81 * 10 meters = so I got the work
of friction to be 98.1 Joules.

Then to find the speed I did

98.1 joules = 10*v^2/2 then got it to equal 4.43 m/s. did I do these steps right? If not can somebody help me? Thanks.
 
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Looks good to me.
 
Doc Al said:
Looks good to me.

Really? Nice. If so thank you. If anyone finds an error please let me know. thank you :)
 

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