How Does Gauss's Law Explain Zero Charge in Hollow Surfaces?

AI Thread Summary
Gauss's Law indicates that the electric field inside a hollow conductor is zero when there is no charge enclosed, which is a key principle in electrostatics. The assumption that a hollow shell has no charge inside is based on the nature of conductors, where free charges reside on the surface. The electric field can exist in regions without charge due to the influence of charges outside the surface, creating a continuous field throughout space. The confusion arises from the distinction between the presence of an electric field and the absence of enclosed charge. Understanding these concepts clarifies how electric fields behave in relation to charged surfaces and empty spaces.
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Hi. My question is straightforward: how do I know when the charge inside a surface is zero?

I've read my textbook chapter twice, but it doesn't offer any explanation on this. In one example problem with a hollow shell, it simply makes the automatic assumption that "there's no charge inside the hollow shell and therefore none inside the guassian surface." I'm baffled as to how they arrived at that conclusion. Am I to assume that anytime a surface has a hollow/empty space in it, the enclosed charge equals zero?

Worse yet, my textbook appears to contradict itself: it states that "the electric field exists at every point in space." But if in some surfaces there's no charge (like the hollow shell), how can the electric field exist!?

Any clarification would be greatly appreciated, especially if it's dumbed down. I feel like this is an elementary concept, but I'm struggling to understand it. :frown:
 
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In a conductor the free charge will be on the surface. And when say that the E field is every where in space, my guess is that they mean its like a continuous fluid and there are no jumps in it.
 
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