How Does Line l Intersect and Divide Line Segment AB in a Maths Challenge?

[aek]

Distinction Maths Challenge

the line 2x + 3y-8=0 cuts the x and y-axis at A and B respectively. The line y=ax+7 is called l. Find

a). in terms of a, the coordinates of the point where l cuts AB (extended).

b). the value of a if l is to divide AB internally in the ratio of 1:3.

please i need your help,
thanks in advance.

 

[Andrew Mason]

the line 2x + 3y-8=0 cuts the x and y-axis at A and B respectively. The line y=ax+7 is called l. Find

a). in terms of a, the coordinates of the point where l cuts AB (extended).

If I cuts AB then the point of intersection (x,y) is a solution to the equations of both lines. So just equate the two and get the expression for x and y in terms of a.

2x + 3(ax + 7) - 8 = 0 so:

x = -13/(3a + 2)

Do the same thing for y.

b). the value of a if l is to divide AB internally in the ratio of 1:3.

A and B are the respective intersections of lines x=0 and y=0 with the line 2x + 3y-8=0. The points (0,A) (B,0) and (0,0) form a triangle with lengths A0B. Find A and B.

If I divides AB at P in a ratio of 1:3 (ie PB/AP = 3) what is the ratio of the x coordinate at P to the x coordinate at B? (draw a vertical line from P to the x-axis (intersecting at x') and compare triangles A0B to Px'B). That will give you the x coordinate of P.

Just substitute the x coordinate of P into the expression for a from 1. to find a.

AM

 

[thepatientmental]

a) To find the coordinates of the point where l cuts AB (extended), we can substitute the equations of the two lines into each other. This will give us a system of equations that we can solve to find the coordinates of the point.

Substituting the equation of line l into the equation of line AB, we get:

2x + 3(ax+7)-8=0

Simplifying, we get:

2x + 3ax + 21 - 8 = 0

Combining like terms, we get:

(2+3a)x + 13 = 0

To solve for x, we can equate the coefficients of x to 0:

2+3a = 0

Solving for a, we get:

a = -2/3

Now, substituting this value of a back into either of the original equations, we can solve for x and y. Let's use the equation of line AB:

2x + 3y - 8 = 0

Substituting a = -2/3, we get:

2x + 3y - 8 = 0

2x + 3(-2/3)x - 8 = 0

Simplifying, we get:

2x - 2x - 8 = 0

0 = 8

This is a contradiction, which means that the lines are parallel and do not intersect. Therefore, there is no point where l cuts AB (extended).

b) To divide AB internally in the ratio of 1:3, we need to find the point on AB that is 1/4 of the distance from A to B. Let's call this point P.

To find the coordinates of P, we can use the formula for finding the coordinates of a point that divides a line segment in a given ratio.

The x-coordinate of P is given by the formula:

xP = (x1 + kx2)/(1+k)

Where x1 and x2 are the x-coordinates of A and B respectively, and k is the ratio in which the line is divided (in this case, 1/4).

Substituting the values, we get:

xP = (0 + 1/4(8))/(1+1/4)

Simplifying, we get:

xP = 2

Similarly, the y-coordinate of P is given by the formula