How Does Magnetic Field Continuity Affect Scalar Potential in Linear Materials?

AI Thread Summary
The discussion focuses on the continuity of the scalar magnetic potential V_m at the boundary of a linear magnetic material. It establishes that V_m must be continuous where the magnetic field H is defined, particularly in the context of a long cylinder immersed in a magnetic field. The user initially struggles to find constants A, B, and C in the potential equations but eventually determines that A equals -H_0. They also discover that the third condition for determining the constants relates to the boundary conditions on H, specifically regarding its perpendicular component. The conversation highlights the complexities involved in applying boundary conditions to solve for magnetic potentials.
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The problem: In the regions of space where \vec{J_f} = 0, the curl of \vec{H} vanishes, and hence we can define a scalar potential V_m.

(a) Show that V_m must be continuous at the boundary of material. - Done

(b) Consider a very long cylinder of radius a made out of a linear magnetic material of relative permeability \mu_r. The axis of the cylinder is oriented along \hat{z} and the cylinder is emerged in a field \vec{H} that is worth H_0 \hat{x} very far from it. From symetrical considerations, V_m must be of the form

V_{m_1}=(As+B/s)cos\phi
V_{m_2}=Cscos\phi

Where V_{m1} is the potential outside the cylinder and V_{m2} the one inside. Find the value of the constant A, B and C in terms of the other parameters.


My solution: I used the condition of continuity to find B in terms of C, and I used the condition at infinity to find A = -H_0.

What is the 3rd condition on V that'll let me find the value of the third constant?
 
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Nerver mind, I found it. It was crazy! It had to do with the boundary conditions on H, expressed as the gradient of V and noticing that in the cylinder along phi = pi/2, the H field is purely solenoidal, then so is the magnetization, which implied that the dot product of the gradient of V outside in the limit s-->a with the normal unit vector is 0, which allowed to recover a second relation btw B and C.

Second Edit: Wrong again! OMG it doesn't end. Finally, I got the right thing. The third relation was lying not to far below the boundary condition on H perpendicular. Much less complicated than what I previcously thought but also much less fun. :frown:
 
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