How Does Nick's Acceleration Change When His Friend Pulls the Rope?

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Nick, an inventive child, uses a rope and pulley system to reach an apple without climbing a tree, pulling with a force of 350 N. His weight is 270 N, and the chair he sits on weighs 160 N, resulting in an upward acceleration of 6.153 m/s². When his friend Barney pulls the rope, the tension remains the same, but the forces acting on Nick and the chair change, affecting the overall dynamics. Participants in the discussion emphasize the importance of drawing a free body diagram to clarify the forces at play. Understanding these changes is crucial for determining Nick's new acceleration when Barney pulls the rope.
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Summary:: An inventive child named Nick wants to reach an apple in a tree without climbing the tree. Sitting in a chair connected to a rope that passes over a frictionless pulley (see figure below), Nick pulls on the loose end of the rope with such a force that the spring scale reads 350 N. Nick's true weight is 270 N, and the chair weighs 160 N. Nick's feet are not touching the ground. Use g=9.8 m/s^2.
a = 6.153 m/s^2
magnitude nick on chair 89.52N
Friend pulling pully: ? m/s^2

An inventive child named Nick wants to reach an apple in a tree without climbing the tree. Sitting in a chair connected to a rope that passes over a frictionless pulley (see figure below), Nick pulls on the loose end of the rope with such a force that the spring scale reads 350 N. Nick's true weight is 270 N, and the chair weighs 160 N. Nick's feet are not touching the ground. Use g=9.8 m/s^2.

Find Nick's acceleration, using upward as positive: a = 6.153 m/s^2

Find the magnitude of the force Nick exerts on the chair: 89.52N

Instead Nick hands the rope with the scale to his friend Barney, who stands on the ground. Barney pulls on the rope so that the spring scale again reads 350 N. What is Nick's acceleration now, again using upward as positive.: ? m/s^2

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Screenshot_20210917-132137_Samsung Notes.jpg


Not sure what changes in the last question T would still equal the same. Not sure what forces changes in the free body diagram, would deeply appreciate any help with the problem.
 
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brandonp620 said:
Not sure what changes in the last question T would still equal the same. Not sure what forces changes in the free body diagram, would deeply appreciate any help with the problem.
The tension in the rope is the same, but the force exerted by the rope on the Nick + chair system is not. Do you see why?
 
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brandonp620 said:
Not sure what changes in the last question T would still equal the same. Not sure what forces changes in the free body diagram, would deeply appreciate any help with the problem.
Please post your FBD for the second part.
 
kuruman said:
The tension in the rope is the same, but the force exerted by the rope on the Nick + chair system is not. Do you see why?
I do not, It would still have the Normal force, and mg and Tension would still be in the same direction. So I'm a little lost. Would there only be one tension force?
 
haruspex said:
Please post your FBD for the second part.
I don't have one because I'm not sure about the difference.
 
brandonp620 said:
Would there only be one tension force?
There are still two tension forces, but what they act on is different.
brandonp620 said:
I don't have one because I'm not sure about the difference.
Think about each in turn. What forces act on Nick now? What forces act on the chair now?
 
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You’re not going to be able to do this without a free body diagram, so please show us your best shot at it. It doesn’t have to be perfect.
 
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