How Does Partial Insertion of a Dielectric Affect Capacitor Voltage?

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In a parallel-plate capacitor initially filled with air, the voltage reading is 46.0 V. When a dielectric fully fills the space, the voltage drops to 15.0 V, indicating a dielectric constant that can be calculated using the formula K = Vo/V. For the scenario where the dielectric is partially removed, the system can be analyzed as two capacitors in series: one with the dielectric and one without. The voltage reading when the dielectric fills only one-third of the space can be determined by applying the principles of series capacitance. Understanding these configurations is crucial for solving the problem effectively.
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A parallel-plate capacitor with only air between the plates is charged by connecting it to a battery. The capacitor is then disconnected from the battery, without any of the charge leaving the plates.

Part A:
A voltmeter reads 46.0 V when placed across the capacitor. When a dielectric is inserted between the plates, completely filling the space, the voltmeter reads 15.0 V. What is the dielectric constant of this material?

Part B:
What will the voltmeter read if the dielectric is now pulled partway out so it fills only one-third of the space between the plates?

I know how to do part A using K = Vo/V, But i do not know how to work the problem if it involve partial dielectric.Any helps or hints would be great thanks.
 
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Think of the system as two separate capacitors. Are they arranged is series or in parallel?
 

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