How Does Static Friction Affect Car Acceleration?

AI Thread Summary
The discussion centers on calculating the maximum acceleration of a 1000kg four-wheel-drive car on a horizontal road, given a coefficient of static friction of 0.80. The initial calculations for static friction yield a force of 7840N, leading to an acceleration of 7.84m/s². However, a participant points out a minor arithmetic error in the static friction calculation, suggesting the correct force should be 7840N instead of 7850N. The method used for the calculations is generally correct, but attention to detail in arithmetic is crucial for accurate results. The conversation emphasizes the importance of precision in physics calculations.
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An automobile with four wheel drive has mass of 1000kg. Its weight is evenly distrubuted among the four wheels, whos coefficient of static friction with the road is 0.80. If the car starts from rest and the road is horizontal calculate the maximum acceleration it can attain without spinning its wheels.

I did:

f = mumg
f = .8(1000)(9.8)
f = 7850

F=ma
7840=1000a
a= 7.84m/s2


Is this correct? If not, where did I go wrong? Thanks. :smile:
 
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physics1234 said:
An automobile with four wheel drive has mass of 1000kg. Its weight is evenly distrubuted among the four wheels, whos coefficient of static friction with the road is 0.80. If the car starts from rest and the road is horizontal calculate the maximum acceleration it can attain without spinning its wheels.

I did:

f = mumg
f = .8(1000)(9.8)
f = 7850

F=ma
7840=1000a
a= 7.84m/s2


Is this correct? If not, where did I go wrong? Thanks. :smile:

Your method looks okay to me, however, you have made a small arithmetical error here;
physics1234 said:
f = .8(1000)(9.8)
f = 7850
 
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