How Does Substituting t=e^x Simplify the Integral Calculation?

eclayj
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Homework Statement



Mathematica's calculation of ∫0Log(2)Sin[(\pi/2)e2x]exdx = -FresnelS[1] + FresnelS[2]

Remembering that FresnelS[x] = ∫0tSin[(\pi/2)t2]dt, You announce that a transformation you can use to help explain Mathematica's output is that every time x goes up by one unit, t=?


Not even sure how to approach this at all. Any suggestions or help on how to start this is appreciated!
 
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I'd start with a quick substitution, t=e^x. That'll make things real easy.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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