How Does Temperature Affect Balloon Volume According to Charles' Law?

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The discussion centers on applying Charles' Law to determine how temperature affects the volume of a balloon. A balloon initially at 22° C and 0.5 liters is placed in a refrigerator at 4° C. The user initially misapplies the formula, leading to confusion about the volume calculation. After clarification, it is noted that using Charles' Law is essential for accurate results, rather than the Ideal Gas Law. The user ultimately resolves the issue by correctly applying Charles' Law to find the new volume of the balloon.
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The temperature inside my refrigerator is about 4° celsius. If I place a balloon in my fridge that initially had a temperature of 22° C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled in my refrigerator?

Ok now the problem I have here is that the teacher says to always convert C to kelvin (i think that's it). And the formula for that is "C° + 273.15". So well uhhh I don't know what my problem is but I have a feeling I didnt do this right. I got V = .53247 liters. Is that right?

What I did was multiplied 295.15 (which is 22° C in kelvin) by 0.5 liters. I got 147.575. So I divided 147.575 by 277.15 (which is 4° C in kelvin) which got me .53247 liters.

Please help cause I just got to know how to do this so I can do the other 20 or so problems.
 
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So, you're showing that the balloon expands as it gets colder? I don't think so.

How you work this rather depends on what you were taught. You can do it with the Ideal Gas Law (assuming pressure remains constant), or you could try Charles' Law:

http://members.aol.com/profchm/charles.html
 
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Yeah my bad I got it working now. I forgot to use Charles law lol.
 

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