How Does the Angle of a Simple Pendulum Affect Its Torque?

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The discussion focuses on calculating the torque of a simple pendulum with a 3.0 kg mass at a 2.0 m length string at angles of 5.0 and 15.0 degrees from the vertical. The torque formula involves either using the force multiplied by the lever arm or the force multiplied by the distance from the pivot to the point of force times the sine of the angle. Clarification is provided that both methods cannot be used simultaneously. Additionally, a correction is made regarding the unit for torque, which is Newton-meters (Nm), not meters (m). Understanding these calculations is essential for analyzing the effects of angle on torque in pendulum motion.
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A simple pendulum consists of a 3.0kg point mass hanging at the end of a 2.0m long light string that is connected to a pivot point.
A. Calculate the magnitude of the torque (due to the force of gravity) around this pivot point when the string makes a 5.0 degree angle with the vertical.
B. Repeat this calculation for an angle of 15.0 degrees.



I do know that the torque equation is torque=forcexlever arm. Also that sinO is included. Also that the units for torque are NxM. I'm having some trouble figuring this out. Please help me. :)
 
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Hi Kiko:)! :smile:

(have a theta: θ :wink:)

No, you don't use both lever arm and sinθ, you use one or the other.

Either use force x (perpendicular) distance from pivot to line of force (= lever arm),

or use force x distance from pivot to point of force x sinθ. :wink:

(oh, and the unit is m, not M)
 

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