silverwhale
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Homework Statement
Show that:
\frac{dx^\nu}{d \lambda} \partial_\nu \frac{dx^\mu}{d \lambda} = \frac{d^2 x^\mu}{d \lambda^2}
The Attempt at a Solution
Well, I could simply cancel the dx^nu and get the desired result; that I do understand.
But what about actually looking at this term alone:
\partial_\nu \frac{dx^\mu}{d \lambda},
calculating it and multiplying with dx^nu/dλ, can I get the same result? I get confused by the question: what if the partial derivative acts on the tangent vector; what happens then?
Thanks for your help!