How does the change in voltage affect the brightness of a light bulb?

AI Thread Summary
The brightness of a light bulb is determined by its power consumption, which is influenced by voltage, current, and resistance. A bulb rated at 1.0W at 6.0V will not shine brighter when the voltage is reduced to 3.0V; instead, its power consumption will decrease. The relationship between power and voltage indicates that reducing voltage affects brightness significantly, as power is proportional to the square of the voltage. Specifically, lowering the voltage from 6V to 3V results in a power consumption of one-fourth of the original. Therefore, the light bulb will shine dimmer at the lower voltage.
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Homework Statement



A light bulbs brightness can be measured by its power consumption. This in turn will depend on the I, V and R of the light bulb. The light bulb is rated at a power consumption of 1.0W when placed at a voltage of 6.0V. We change the battery from a 6.0V to a 3.0V one. Will the light bulb shine brighter than the previous case. What will be the current through the light bulb


Homework Equations



P=IV


The Attempt at a Solution



Is the power consumption 1.0W for both cases
If it is then I1=1/6 and I2 =1/3 Therefore the latter example will shine brighter

If not how do i take into account the changing power
 
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It says that the power consumption is of 1 W whan placed at 6 V, not all the time. You might want to calculate, say, resistance of the light bulb (P=IU=U^2/R), what should then allow you to calculate the power consumption of the same bulb placed at 3V.
 
You could also notice that
p \alpha V^2
so decreasing V by \frac{1}{2} decreases p by \frac{1}{4}

or you could multiply out the old V^2 and multiply the new one in:
p_{3V} = p_{6V}\frac{3^2}{6^2}=p_{6V}\frac{1}{4}
 
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