How Does the Doppler Effect Alter Wavelength as a Train Approaches?

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The Doppler Effect alters the wavelength of sound as a train approaches, changing it from 0.279 meters to 0.268 meters due to the train's speed of 50 meters per second. The original frequency of the train whistle is 1200 Hz, and the speed of sound is 335 meters per second. By applying the formula for wavelength, the calculations show that the approaching train compresses the sound waves, resulting in a shorter wavelength. The change in wavelength reflects the increase in frequency perceived by an observer as the train moves closer. This demonstrates the fundamental principles of the Doppler Effect in sound waves.
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1.) Suppose the sound from an approaching train whistle normally has a frequency of 1200 cycles per second, but the train is approaching at 50 meters per second. How would the Doppler Effect change the wavelength of the sound? (speed of sound 335 meters per second; I would like a quantitative answer here for full credit)

So far I have done the following: c = wavelength (frequency)
335 = wavelength (1200)
335/1200 = wavelength
wavelength = .279
wavelength = 2.79 x 10^-1 meters

c = wavelength (frequency)
335 = wavelength (1200 + 50)
335/1250 = wavelength
wavelength = .268
wavelength = 2.7 x 10^-1 meters

These are the forumlas I have from class, but I don't know any other way to solve the problem or if it is right.
 
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The Doppler Effect would change the wavelength of the sound from 2.79 x 10^-1 meters to 2.7 x 10^-1 meters.
 
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