How does the frequency of a wave affect its power transmission?

AI Thread Summary
The discussion centers on how the frequency of a wave affects its power transmission in two identical strings under the same tension. Wave A has a frequency twice that of wave B, leading to a calculation of power using the formula P = (1/2)μω²A²v. The initial conclusion was that Wave A transmits energy at twice the rate of Wave B, but further analysis revealed that the power is actually four times greater due to the relationship between frequency and angular frequency (ω = 2πf). The correct answer is confirmed as D, indicating that higher frequency waves transmit more power significantly. Understanding the impact of frequency on power transmission is crucial in wave mechanics.
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Homework Statement



Two identical but separate strings, with the same tension, carry sinusoidal waves with the same amplitude. Wave A has a frequency that is twice that of wave B and transmits energy at a rate that is ____ that of wave B.
A) half
B) twice
C) one fourth
D) four times
E) eight times

Homework Equations



P = \frac{1}{2}\mu\omega^{2}A^{2}v
v = \lambdaf

The Attempt at a Solution



V_{B} = \lambdaf_{B}
V_{A} = \lambda(2f_{B}) = 2V_{B}
P_{B} = \frac{1}{2}\mu\omega^{2}A^{2}v_{B}
P_{A} = \frac{1}{2}\mu\omega^{2}A^{2}2v_{B} = 2P_{B}

Thus my answer is B.

However, the answer key says D. What did I do wrong?
 
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If the strings are identical (same mu) and have the same tension, the velocity v is also identical. You can't assume lambda is the same, it can't be. What changes in your power formula is omega. How much does it change?
 
Ah okay, so w = 2pi / f.
Therefore the Pa = 4Pb.
Thank you, that makes sense.
 
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