How does the missing + sign in the equation affect the trajectory of a particle?

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The discussion centers on the implications of a missing + sign in a particle's motion equation, which may lead to incorrect calculations of acceleration. Participants note that the equation assumes constant force and acceleration due to a small time interval, which complicates the analysis. The relationship between potential V(x) and force is questioned, highlighting the distinction between speed and velocity in the context of the problem. It is emphasized that treating the quantities as speeds instead of velocities requires a more complex case-by-case analysis. Overall, the missing + sign significantly impacts the trajectory calculations and the interpretation of motion dynamics.
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Homework Statement
Consider an atom of mass m moving along the x
direction with an initial position x1 and initial speed v1. If the
atom moves for a time interval Δt in a region where the potential energy varies as V(x), what is its speed v2 at position x2?
Relevant Equations
Ek=(mv^2)/2
Fx=-dV/dx
E=Ek+V
Can someone explain how can i get that answer?
 

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At first sight, the equation looks like there is a + sign missing.
 
What they appear to have done (though as @PeroK points out, the answer appears to be incorrect), is calculate the acceleration and then use the equations of accelerated motion. The answer also appears to be assuming that ##\Delta t## is small, so the force and acceleration are treated as constant.

What is the relationship between potential V(x) and force? How is force related to acceleration and velocity?
 
PeroK said:
At first sight, the equation looks like there is a + sign missing.
Even that doesn’t fix it.
They have created a problem for themselves by referring to speed instead of velocity.
In velocities it would be ##\vec v_2=\vec v_1-\frac{dV}{dx}\frac{\Delta t}m\hat x##.
To rewrite that in terms of speeds (##|\vec v_i|##) would involve breaking it into cases.
 
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