How does the moment of inertia scale?

AI Thread Summary
When scaling an object by a factor f, its volume and mass increase by f^3, while the moment of inertia scales by f^5. The moment of inertia is calculated using the equation I = k * m * r^2, where k is a shape-dependent constant. For a 1/48 scale model with a rotational kinetic energy of 2.5J, the full-scale object's kinetic energy, rotating at the same angular velocity, would be 2.5J multiplied by (48^5). Understanding these relationships is crucial for solving problems related to moment of inertia and kinetic energy in scaled models. The discussion emphasizes the importance of recognizing how scaling affects physical properties.
student34
Messages
639
Reaction score
21

Homework Statement



If we multiply all of the design dimensions by a scaling factor f, it's volume and mass will be multiplied by f^3. (a) By what factor will its moment of inertia be multiplied? (b) And if a 1/48 scale model has a rotational kinetic energy of 2.5J, what will be the kinetic energy for the full-scale object of the same material rotating at the same angular velocity?

Homework Equations



The Attempt at a Solution



I have absolutely no idea what they are talking about. I feel like I missed an entire chapter, but I am sure that I didn't. All the other questions in my book leading up to this one have been the usual ones that ask me to find a value when dealing with the moment of inertia. What is this asking.
 
Physics news on Phys.org
Scale Factors

If you look at some of the moment of inertia equations you know, you'll see how we can address this question.

For a point mass, it's I = \frac{2 m r^2}{5}. For a solid sphere, I = \frac{2 m r^2}{5}. For a hollow sphere, I = \frac{2 m r^2}{3}. Rod about the end I = \frac{1 m r^2}{3}. Rod about the middle: I = \frac{1 m r^2}{12}.

The only thing that is changing is the constant in front.

The moment of inertia is given by the equation I=k*m*r^2, where k is the constant that depends on the shape. So the moment increasesas the mass increases, and increases like the square of the radius.

To find the scaling, you just multiply each quantity by a scale factor, f. We have to multiply by f3 for mass (since mass increases with increasing *volume*). We multiply each term of r by f.

Hope that helps.

Dr Peter Vaughan
BASIS Peoria Physics
 
sonnyfab said:
If you look at some of the moment of inertia equations you know, you'll see how we can address this question.

For a point mass, it's I = \frac{2 m r^2}{5}. For a solid sphere, I = \frac{2 m r^2}{5}. For a hollow sphere, I = \frac{2 m r^2}{3}. Rod about the end I = \frac{1 m r^2}{3}. Rod about the middle: I = \frac{1 m r^2}{12}.

The only thing that is changing is the constant in front.

The moment of inertia is given by the equation I=k*m*r^2, where k is the constant that depends on the shape. So the moment increasesas the mass increases, and increases like the square of the radius.

To find the scaling, you just multiply each quantity by a scale factor, f. We have to multiply by f3 for mass (since mass increases with increasing *volume*). We multiply each term of r by f.

Hope that helps.

Dr Peter Vaughan
BASIS Peoria Physics

Oh, thank-you so much!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top