How Does Voltage Affect Charge in Biological Capacitors?

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In a discussion about simulating a biological system as a parallel plate capacitor, the relationship between charge (Q) and voltage (V) is examined. It is clarified that increasing voltage typically leads to an increase in charge, contradicting the idea that charge remains constant regardless of voltage changes. The conversation highlights the importance of understanding this relationship in the context of capacitor behavior. The user acknowledges that setting a maximum theoretical charge value could be feasible in their simulation. Ultimately, the interaction emphasizes the fundamental principles of capacitance in biological systems.
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Homework Statement



I am simulating a Biological system. For ease just consider it as a parallel plate capacitor. Now the simulation software takes the value of charge Q, but not the value of V. Now as C=Q/V, can we say that the charge Q of a parallel plate capacitor remains constant and V (say we increase from 5-8 volts) has no effect on Q of the capacitor.
 
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Oscar6330 said:
I am simulating a Biological system. For ease just consider it as a parallel plate capacitor. Now the simulation software takes the value of charge Q, but not the value of V. Now as C=Q/V, can we say that the charge Q of a parallel plate capacitor remains constant and V (say we increase from 5-8 volts) has no effect on Q of the capacitor.

Hi Oscar6330! :smile:

Perhaps I'm misunderstanding the biology, but the whole point of a capacitor is that when you increase the voltage, you increase the build-up of charge (until the capacitor breaks down by a spark jumping across it).
 


tiny-tim said:
Hi Oscar6330! :smile:

Perhaps I'm misunderstanding the biology, but the whole point of a capacitor is that when you increase the voltage, you increase the build-up of charge (until the capacitor breaks down by a spark jumping across it).

Hey thanks for the reply. Hence this means that if I put the max theoratical Q value, I will be able to do it.
 

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