How Does Voltage Affect Charge in Biological Capacitors?

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SUMMARY

The discussion centers on the relationship between voltage (V) and charge (Q) in biological capacitors, modeled as parallel plate capacitors. It is established that increasing voltage directly increases the charge build-up until the capacitor reaches its breakdown point. The formula C=Q/V indicates that charge is dependent on voltage, contradicting the idea that charge remains constant regardless of voltage changes. Participants confirm that higher voltage results in greater charge accumulation in the capacitor.

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  • Understanding of capacitor fundamentals, specifically parallel plate capacitors.
  • Familiarity with the relationship between charge, voltage, and capacitance (C=Q/V).
  • Basic knowledge of electrical breakdown phenomena in capacitors.
  • Experience with simulation software for biological systems.
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  • Explore the breakdown voltage of different capacitor types.
  • Learn about biological capacitors and their unique properties.
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Electrical engineers, biophysicists, and researchers involved in simulating biological systems or studying capacitor behavior in biological contexts.

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capacitor problem! (Advanced)

Homework Statement



I am simulating a Biological system. For ease just consider it as a parallel plate capacitor. Now the simulation software takes the value of charge Q, but not the value of V. Now as C=Q/V, can we say that the charge Q of a parallel plate capacitor remains constant and V (say we increase from 5-8 volts) has no effect on Q of the capacitor.
 
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Oscar6330 said:
I am simulating a Biological system. For ease just consider it as a parallel plate capacitor. Now the simulation software takes the value of charge Q, but not the value of V. Now as C=Q/V, can we say that the charge Q of a parallel plate capacitor remains constant and V (say we increase from 5-8 volts) has no effect on Q of the capacitor.

Hi Oscar6330! :smile:

Perhaps I'm misunderstanding the biology, but the whole point of a capacitor is that when you increase the voltage, you increase the build-up of charge (until the capacitor breaks down by a spark jumping across it).
 


tiny-tim said:
Hi Oscar6330! :smile:

Perhaps I'm misunderstanding the biology, but the whole point of a capacitor is that when you increase the voltage, you increase the build-up of charge (until the capacitor breaks down by a spark jumping across it).

Hey thanks for the reply. Hence this means that if I put the max theoratical Q value, I will be able to do it.
 

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