How Does Voltage Affect the X-ray Emission Spectrum of Molybdenum?

justinegauci
Messages
1
Reaction score
0
About the intensity of x-ray emission spectrum of Molybdenum as a function of wavelength for various applied voltages:

Explain fully:

1) the production of continuous radiation emitted
2) the absence of radiation of wavelength shorter than the minimum wavelength
3) the presence of the peaks K(alpha) and K(beta)
4) the absence of the K peaks in lower curves

5) Explain why in x-rays if any line in the K series is emitted, then the whole series is emitted.
6) Why does each series converge to a short wavelength limit?

7) The K-absorption edge of tungsten is 0.0178nm and the average wavelengths of the K series lines are: K(alpha)=0.0210nm and K(beta)=0.0184nm.
i) What is the least energy in eV required to excite the L series?
ii) What is the wavelength of the L(alpha) line?
 
Physics news on Phys.org
Hello justinegauci.What have you tried and where are you stuck?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top