How Does Work Affect the Energy of a Helium Nucleus?

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The discussion revolves around calculating the energy values of a helium nucleus under the influence of an electric force. The initial values provided include a particle energy of 8.897e-10 J, rest energy of 3.06e-10 J, and kinetic energy of 5.83e-10 J. The user seeks assistance in recalculating these values after an electric force does 4.2x10-9 J of work on the nucleus, emphasizing the need for relativistic equations. Key equations mentioned include the rest energy formula and the total energy calculation, which incorporates the relativistic factor. The user ultimately resolves the issue independently, indicating a successful understanding of the concepts.
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A helium nucleus has mass 3.4e-27 kg. If its speed |v| is 0.939c (that is, |v|/c = 0.939), what are the following values?
particle energy = 8.897e-10 J

rest energy = 3.06e-10J

kinetic energy = 5.83e-10J

i found those but now i can't figure this out:

Next an electric force acts on the helium nucleus and does 4.2x10-9 J of work on the particle. Now what are the following values?
particle energy = J

rest energy = J

kinetic energy = J

please help me!
 
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You have to use the relativistic equations

Rest energy = E = M * C * C
Total energy = Rest energy + K.E
(No, K.E is not 0.5 m*v*V!)

As the v/c = 0.939, we can not ignore relativistic effects

relativistic factor g = 1/sqrt((1- (v/c)^2)

So total energy = rest energy * g

K.E = total energy - rest energy
 
i know that idk how to do it when there is a force i already solved for that

nvm figured it out thanks
 
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