How Far Does a Car Slide on Wet Concrete Before Stopping?

AI Thread Summary
A 1000kg car skidding at 40m/s on wet concrete experiences a friction force of 6000N. The initial attempt to calculate the stopping distance using the centripetal force equation was incorrect. The discussion emphasizes the need to apply the work-energy principle instead of centripetal force for this scenario. The confusion about positive and negative values in calculations is addressed, highlighting the importance of defining direction in physics problems. Properly applying the work-energy approach will yield the correct stopping distance.
astru025
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Ap physics friction force please help!

Homework Statement



A 1000kg car traveling at a speed of 40m/s skids to a halt on wet concrete where the friction force is 6000N. How far does the car slide before coming to a stop?

Homework Equations




F=mv^2 / r
1000 kg x (40 m/s^2) / r = 6000 N
I got 266.7


The Attempt at a Solution


I came up with a positive number and it should be a negative number... What am I doing wrong?!
 
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Why would you expect a negative number?
(And don't forget units.)

F=mv^2/r is for centripetal force isn't it? Is the car going in a circle?
 
astru025 said:

Homework Statement


I came up with a positive number and it should be a negative number... What am I doing wrong?!
Well..it always depends on which direction you choose to be positive and which negative.
However, the equation you used wasn't correct. Think it in terms of work and energy.
 
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