How Far Will a Box Slide with a Coefficient of Kinetic Friction of 0.23?

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To determine how far a box will slide with a coefficient of kinetic friction of 0.23 after an initial push of 4.2 m/s, one can apply principles of physics, specifically energy methods or kinematics. The problem is similar to another example where a box with a coefficient of 0.20 slides after being pushed to an initial speed of 4.0 m/s, yielding a calculated distance of 4.1 meters. The weight of the box is not necessary for the calculation, as the frictional force can be determined from the coefficient alone. Participants in the discussion emphasize the importance of understanding the underlying equations, suggesting that basic calculus knowledge is beneficial. Ultimately, the conversation highlights the collaborative effort to solve the problem and clarify the methods involved.
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If the coefficient of kinetic friction of a box is 0.23, how would you find out how far the box would travel with an initial push of 4.2 m/s? Assume the "push" has already happened.
 
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it's a different problem...that's all the info I've been given...i don't know how the speed factors into the problem...i don't know the object's weight or anything else
 
did you read the solution, there's no mass involved.

"A box is given a push so that it slides across the floor. How far will it go given that the coefficient of kinetic friction is .20 and the push imparts an initial speed of 4.0 m/s?"

go back and actually read it. this problem is identical to yours. Then tell me where your getting stuck, if you do get stuck.
 
the answer to the problem you wrote is actually 4.1 meters but i don't know how that answer was reached
 
read the solution i posted! lol, don't sweat it will work it out together, just tell me if you have learned energy methods yet or not, so I will know which approach is appropriate.
 
and how did you happen to change the numbers around so that they were identical to a problem in my textbook?
 
which method do you want to use jshaner?
 
thanks...i'm sorry i didn't see the link that you put up there...thanks so much...i was able to get the answer, but those equations are a little beyond where we're at right now...thanks again.
 
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well, they are really quite simple, as long as you know basic calculus. and its very straight forward, we can go over them if you would like.
 
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