How Far Will a Bundle Slide Up an Incline with Friction?

  • Thread starter Thread starter h7u9i
  • Start date Start date
  • Tags Tags
    Incline Movement
AI Thread Summary
A 4.0 kg bundle with 128 J of kinetic energy starts sliding up a 30° incline with a coefficient of friction of 0.30. Initial calculations for the normal force and friction were incorrect, leading to an estimated distance of 6.2 m. The correct normal force should be calculated as N=mgcos(30°), which adjusts the frictional force. After correcting the calculations, the distance the bundle slides up the incline is determined to be 4.3 m. Understanding the relationship between forces and drawing a free body diagram is essential for solving such problems.
h7u9i
Messages
1
Reaction score
0
A 4.0 kg bundle starts up a 30° incline with 128 J of kinetic energy. How far will it slide up the plane if the coefficient of friction is 0.30?So, I began finding the Normal
N=W(y)=4cos30=3.46

Then found friction

f=uN
f=.3*3.46=1.04

So
E=E
K=Ug + Q
K=mgh + fd
K=mg(dsin30)+fd
128=4(9.8)(.5)d+(1.04)d
128=20.64d
d=6.2m

But the answer says 4.3m. What's wrong?

Thanks!

EDIT:
So I figured it out... N=4*9.8cos30. Duh.
 
Last edited:
Physics news on Phys.org
h7u9i said:
So I figured it out...
Glad things worked out. By the way, welcome to Physics Forums!
 
I had a similar problem (just the numbers changed). I get the whole h = dsin(30) thing, but why does Fn = mgcos(30)?
 
Ghostscythe said:
I had a similar problem (just the numbers changed). I get the whole h = dsin(30) thing, but why does Fn = mgcos(30)?
Draw a free body diagram. Take the direction of the normal force as the y-direction, apply Fnet=ma to the y-direction, and solve for Fn.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top