How Far Will the Spring Compress When a 1.5kg Object Is Dropped?

AI Thread Summary
A 1.5kg object is dropped from a height of 1.2m onto a spring with a force constant of 320N/m. The initial approach used the conservation of energy equation mgh=0.5kx^2, but the calculated answer differed from the book's. The user later realized the discrepancy was due to the book using g=10 m/s² instead of the more precise 9.81 m/s². The discussion confirms that the second attempt at solving the problem was indeed correct. The key takeaway is the importance of consistent gravitational acceleration values in calculations.
semc
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A 1.5kg object is held 1.2m above a spring with force constant 320N/m. The object is dropped on the spring how far does the object compress the spring?

Alright so what i did was mgh=0.5kx^2 but the answer is different from the book. I guess is when the object touches the spring, its exerting a force downward to the spring due to gravity so i tried mg(h+x)=0.5kx^2 and solve the equation however this is wrong again...Can someone tell me what's wrong?
 
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semc said:
...so i tried mg(h+x)=0.5kx^2 and solve the equation however this is wrong again...Can someone tell me what's wrong?
That should work just fine. (It's a conservation of energy problem.) Why do you say it's wrong?
 


So you mean my second attempt is correct? Well, the answer i got is different from the one in my book.
 


semc said:
So you mean my second attempt is correct?
Yes.
Well, the answer i got is different from the one in my book.
Show what you did and what the book says.
 


Hey doc my bad. The book uses g=10 instead of 9.81 hence the difference sorry about that. Thanks man!
 
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