How Fast Can a Racing Car Go Before Losing Traction Compared to a Standard Car?

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A standard car can reach a maximum speed of 85 mph before losing traction while driving in a circle. The racing car, equipped with double the downforce, will have a different critical speed due to this increased downforce affecting the coefficient of grip. The formula provided, v = √(u g r), indicates that the mass of the car is not directly included, as it cancels out, suggesting that the racing car's downforce should be factored into the coefficient of grip. Understanding how downforce modifies the grip coefficient is key to calculating the racing car's critical speed. Further exploration of the formula's derivation and the impact of downforce is necessary for a complete solution.
AJH1
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Hi,

I'm new to the forum and this is my first post...so go easy!
I have a physics problem to solve and if possible I would love a bit of help here.

This is the question:
A standard car is driven around in a measured circle, increasing its speed as it goes and is able to reach 85mph before it loses traction and slides away. A racing car, with spoilers and wings fitted, produces twice the amount of downforce as the standard car. It is driven around the same circle and in the same circumstances. How fast can the racing car drive around the circle until it too breaks away and loses traction.
The formula given to calculate the answer is:

v =[Square root of] u g r (where v = final velocity, u = co-efficient of grip and is a constant, g = gravity, and r = radius of circle.)

Given that gravity would normally be a constant at land level (I believe) and the coefficient of grip is a constant, I am struggling to understand how the doubled downforce would fit into this equation. Hence, how would I calculate the critical speed of the racing car?

Any help here would be much appreciated.

AJH.
 
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Hi and welcome to PF.
If this is a homework / coursework question it really should be in the appropriate forum (see rules at the top of the General Physics Forum.
Do you have any ideas about this, before PF steps into help? We do so hate to spoon feed people. Looking at that formula, do you know how it has been arrived at? In arriving at it, the mass of the car (leading to its weight) has been canceled out. That formula, as it stands, assumes that just the mass of the car is involved. What should be different in the formula when applied to the racing car? (Going back to the basic formula and derivation could give you a clue about that.)
See this link
and this link
See if you can figure it out, with the help of the links.
 
I think it's easist first to watch a short vidio clip I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way? The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...

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